C语言经典算法100例

由天下分享时间：2025/6/7 1:53:29 加入收藏我要投稿点赞

initgraph(&driver,&mode,\ x1=x2=y1=y2=10; dx1=dy1=2; dx2=dy2=3; while(!kbhit()) {

line(x1,y1,x2,y2); x1+=dx1;y1+=dy1; x2+=dx2;y2+dy2;

if(x1<=LEFT||x1>=RIGHT) dx1=-dx1;

if(y1<=TOP||y1>=BOTTOM) dy1=-dy1;

if(x2<=LEFT||x2>=RIGHT) dx2=-dx2;

if(y2<=TOP||y2>=BOTTOM) dy2=-dy2; if(++count>LINES) {

setcolor(color);

color=(color>=MAXCOLOR)?0:++color; } }

closegraph(); }

【程序61】

题目：打印出杨辉三角形（要求打印出10行如下图） 1.程序分析： 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 2.程序源代码： main() {int i,j; int a[10][10]; printf(\ for(i=0;i<10;i++) {a[i][0]=1; a[i][i]=1;} for(i=2;i<10;i++)

for(j=1;j a[i][j]=a[i-1][j-1]+a[i-1][j];

for(i=0;i<10;i++) {for(j=0;j<=i;j++) printf(\ printf(\ } }

============================================================== 【程序62】

题目：学习putpixel画点。 1.程序分析： 2.程序源代码： #include \ #include \ main() {

int i,j,driver=VGA,mode=VGAHI; initgraph(&driver,&mode,\ setbkcolor(YELLOW); for(i=50;i<=230;i+=20) for(j=50;j<=230;j++) putpixel(i,j,1); for(j=50;j<=230;j+=20) for(i=50;i<=230;i++) putpixel(i,j,1); }

============================================================== 【程序63】题目：画椭圆ellipse 1.程序分析： 2.程序源代码： #include \ #include \ #include \ main() {

int x=360,y=160,driver=VGA,mode=VGAHI; int num=20,i; int top,bottom;

initgraph(&driver,&mode,\ top=y-30; bottom=y-30; for(i=0;i{

ellipse(250,250,0,360,top,bottom); top-=5;

bottom+=5; } getch(); }

============================================================== 【程序64】

题目：利用ellipse and rectangle 画图。 1.程序分析： 2.程序源代码： #include \ #include \ #include \ main() {

int driver=VGA,mode=VGAHI; int i,num=15,top=50; int left=20,right=50; initgraph(&driver,&mode,\ for(i=0;i{

ellipse(250,250,0,360,right,left); ellipse(250,250,0,360,20,top);

rectangle(20-2*i,20-2*i,10*(i+2),10*(i+2)); right+=5; left+=5; top+=10; } getch(); }

============================================================== 【程序65】

题目：一个最优美的图案。 1.程序分析： 2.程序源代码： #include \ #include \ #include \ #include \ #include \ #include \ #include \ #define MAXPTS 15 #define PI 3.1415926 struct PTS { int x,y;

};

double AspectRatio=0.85; void LineToDemo(void) {

struct viewporttype vp; struct PTS points[MAXPTS]; int i, j, h, w, xcenter, ycenter; int radius, angle, step; double rads;

printf(\ getviewsettings( &vp ); h = vp.bottom - vp.top; w = vp.right - vp.left;

xcenter = w / 2; /* Determine the center of circle */ ycenter = h / 2;

radius = (h - 30) / (AspectRatio * 2);

step = 360 / MAXPTS; /* Determine # of increments */ angle = 0; /* Begin at zero degrees */

for( i=0 ; irads = (double)angle * PI / 180.0; /* Convert angle to radians */ points[i].x = xcenter + (int)( cos(rads) * radius );

points[i].y = ycenter - (int)( sin(rads) * radius * AspectRatio ); angle += step; /* Move to next increment */ }

circle( xcenter, ycenter, radius ); /* Draw bounding circle */

for( i=0 ; ifor( j=i ; jmoveto(points[i].x, points[i].y); /* Move to beginning of cord */ lineto(points[j].x, points[j].y); /* Draw the cord */ } } } main()

{int driver,mode;

driver=CGA;mode=CGAC0; initgraph(&driver,&mode,\ setcolor(3); setbkcolor(GREEN); LineToDemo();}

============================================================== 【程序66】

题目：输入3个数a,b,c，按大小顺序输出。 1.程序分析：利用指针方法。 2.程序源代码： /*pointer*/ main() {

int n1,n2,n3;

int *pointer1,*pointer2,*pointer3;

printf(\ scanf(\ pointer1=&n1; pointer2=&n2; pointer3=&n3;

if(n1>n2) swap(pointer1,pointer2); if(n1>n3) swap(pointer1,pointer3); if(n2>n3) swap(pointer2,pointer3);

printf(\ }

swap(p1,p2) int *p1,*p2; {int p;

p=*p1;*p1=*p2;*p2=p; }

============================================================== 【程序67】