(3)查表 E0Ag+/Ag)=0.7996V E0Cu2+/Cu)=0.3419V 0.059lgc(Ag+)/c0EAg+/Ag)=E0Ag+/Ag)+z =0.7996+0.0592lg0.5=0.7818V
0.0592+0lgc(Cu)/c0 E(Cu2+/Cu)=ECu2+/Cu)+z =0.34 19V+0.0296lg0.5=0.3330V
E =E(Ag+/Ag)-E(Cu2+/Cu) =0.7818V-0.3330V=0.4488V
可逆电池的电动势及其应用的分章练习题
(3)查表E0Ag+/Ag)=0.7996VE0Cu2+/Cu)=0.3419V0.059lgc(Ag+)/c0EAg+/Ag)=E0Ag+/Ag)+z=0.7996+0.0592lg0.5=0.7818V0.0592+0lgc(Cu)/c0E(Cu2+/Cu)=ECu2+/Cu)+z=0
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