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二次函数动点问题解答方法技巧(含例解答案)

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又?点B在y??3x?b上 43?0???b

23b?

233···················································································· 2分 ?BC的解析式为y??x? ·

4232?y??x?3?x1??1???4(2)由?,得?9

y1??y??3x?3??4??429???C??1,?,B(2,0)

4???x2?2 ························································· 4分 ?y?0?29 ······································································································· 5分 4199································································································ 6分 ?S△ABC??4?? ·

242(3)过点N作NP?MB于点P ?EO?MB ?NP∥EO

······································································································· 7分 ?△BNP∽△BEO ·

BNNP ···················································································································· 8分 ??BEEO?AB?4,CD?由直线y??33?3?x?可得:E?0,? 42?2?35?在△BEO中,BO?2,EO?,则BE?

2262tNP,?NP?t ······························································································· 9分 ??5352216?S??t?(4?t)

25312·························································································· 10分 S??t2?t(0?t?4) ·

55312······································································································ 11分 S??(t?2)2?

5512?此抛物线开口向下,?当t?2时,S最大?

512····························· 12分 ?当点M运动2秒时,△MNB的面积达到最大,最大为. ·5

二次函数动点问题解答方法技巧(含例解答案)

又?点B在y??3x?b上43?0???b23b?233····················································································2分?BC的解析式为y??x?·4232?y??x?3?x1??1???4(2)由?,得?9y1?
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